Probability Of A Combination Of Two Events Mutually Foreign
Probability of a combination of two events mutually foreign are an probability of a combination of two events that are not interconnected with each other or can be called mutually foreign.
Information :
Resolution:
The above question is a matter of foreign mutual occurrence, becouse there will never be the same members between odd prime members and even members of the number. For more details see the picture below:
S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
n(S) = 10
A = {2, 4, 6, 8,10}
n(A)= 5
P(A) = 5/10
B = {3, 5, 7}
n(B) = 3
P(B) = 3/10
P(A∪B) = P(A) + P(B)
P(A∪B) = 5/10 + 3/10
P(A∪B) = (5 + 3)/10
P(A∪B) = 8/10
P(A∪B) = 0.8
So the probability of occurrence of an even number or odd prime number is 0.8.
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Reference :
Formula of Probability of A Combination of Two Events Mutually foreign
P(A∪B) = P(A) + P(B)
Information :
P (A∪B) = Probability of Event A or B
P (A) = Probability occurrence A
P (B) = Probability occurrence B
Example of Probability of A Combination of Two Events Mutually foreign
In a bag there are 10 cards, each numbered consecutively, a card drawn from the bag at random, for example A is the event that the even-numbered cards are taken and B is the occurrence of an odd numbered prime card. Look for an A or B chance occurrence!
Resolution:
The above question is a matter of foreign mutual occurrence, becouse there will never be the same members between odd prime members and even members of the number. For more details see the picture below:
S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
n(S) = 10
A = {2, 4, 6, 8,10}
n(A)= 5
P(A) = 5/10
B = {3, 5, 7}
n(B) = 3
P(B) = 3/10
P(A∪B) = P(A) + P(B)
P(A∪B) = 5/10 + 3/10
P(A∪B) = (5 + 3)/10
P(A∪B) = 8/10
P(A∪B) = 0.8
So the probability of occurrence of an even number or odd prime number is 0.8.
Just this article which I can share to you.
I apologize if there are wrong word on this article
The end of word wassalamualaikum wr. wb.
Reference :
- The mathematics book of the high school class XI IPA program
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